View Single Post
  (#5 (permalink)) Old
Hyper Sonic Offline
Banned
I can't get enough
*********
 
Hyper Sonic's Avatar
 
Gender: Male
Location: England

Posts: 2,022
Points: 25,325, Level: 23
Points: 25,325, Level: 23 Points: 25,325, Level: 23 Points: 25,325, Level: 23
Blog Entries: 23
Join Date: January 5th 2009

Re: Somebody Wanna Help Me With My Homework?? - March 26th 2009, 10:38 PM

Quote:
Originally Posted by Christinaa317o8 View Post
So here's my questions.
We're working on ratios which was from 9th grade algerabra but i don't understand it.
Pretty pathetic my teacher tells me.

Okay so heres the problem:

A line segment is divided into two segments, that are in the ratio 3:5. The measure of one segment is 12 centemeters longer than the measure of the other. Find the measure of each segment.


---So I drew a picture of a line. with a point dividing it into two. named one 3x and the other 5x. Thats all I have and its probably wrong. :]
I'd have done the same thing. You also know that
Code:
5x = 3x + 12
which solves to give x = 6. Putting that back in we get 3x6cm = 18cm and 5x6cm = 30cm. As 30cm is 12cm bigger than 18cm the answer of 6cm is correct


Quote:
Heres another question

Can the measures of a triangle be in the ratio 5:6:7? Why or Why not?
By measures do you mean angles or lines?

I don't see why angles cannot. Since the sum of the angles in a triangle is 180 you can do
Code:
180/(5+6+7) = 10
so you could have 50, 60 and 70 degrees.

With sides I do not think so because if I construct a triangle with sides a=7x, b=6x and c=5x then by using the cos rule
Code:
cos(C) = (a²+b²-c²)/(2ab)
would give an angle of 0 degrees which evidently cannot be