Somebody Wanna Help Me With My Homework??
 

I don't know if anyone posts this stuff, but I really suckkk at Geometry, so if anyone happens to be wicked good, can you let me know if you wanna help?

;]

Re: Somebody Wanna Help Me With My Homework??
 

Re: Somebody Wanna Help Me With My Homework??
 

I'm pretty decent at Geometry. What did you need help with?

Re: Somebody Wanna Help Me With My Homework??
 

So here's my questions.
We're working on ratios which was from 9th grade algerabra but i don't understand it.
Pretty pathetic my teacher tells me.

Okay so heres the problem:

A line segment is divided into two segments, that are in the ratio 3:5. The measure of one segment is 12 centemeters longer than the measure of the other. Find the measure of each segment.


---So I drew a picture of a line. with a point dividing it into two. named one 3x and the other 5x. Thats all I have and its probably wrong. :]

Heres another question

Can the measures of a triangle be in the ratio 5:6:7? Why or Why not?

Re: Somebody Wanna Help Me With My Homework??
 

I'd have done the same thing. You also know that

Code:

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5x = 3x + 12

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which solves to give x = 6. Putting that back in we get 3x6cm = 18cm and 5x6cm = 30cm. As 30cm is 12cm bigger than 18cm the answer of 6cm is correct

By measures do you mean angles or lines?

I don't see why angles cannot. Since the sum of the angles in a triangle is 180 you can do

Code:

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180/(5+6+7) = 10

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so you could have 50, 60 and 70 degrees.

With sides I do not think so because if I construct a triangle with sides a=7x, b=6x and c=5x then by using the cos rule

Code:

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cos(C) = (a²+b²-c²)/(2ab)

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would give an angle of 0 degrees which evidently cannot be

Re: Somebody Wanna Help Me With My Homework??
 

I know you don't need anything from me, but what all of what Hypersonic did all looks right. Except I think that sides of a triangle 5,6,7 could work.

cheers

Re: Somebody Wanna Help Me With My Homework??
 

For the last question : Try pythagorus or trig :)

Re: Somebody Wanna Help Me With My Homework??
 

thankks so muchhh
:]

the second question was suppossed to say measures of the sides**



How do you do these?

The line segments ABC and PQR are divided proportionally by B and Q. AB<BC and PQ<QR.

12. Find PQ when AB = 15, BC = 25, and QR=35.

----I think I might know how to set it up but the wording kind of confuses me.

Re: Somebody Wanna Help Me With My Homework??